Question 548494: find three consecutive odd integers such that the sum of the first two is 29 more than the third Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! Let the lesser of the three consecutive odd integers be .
Consecutive odd integers differ by 2.
The other two consecutive odd integers would be , and .
Do not worry about their being odd at this point. We can always discard any even solutions at the end. (And, by the way, we would set the problem the same way if it was about three consecutive even numbers).
The sum of the first two is .
29 more than the third is
The problem says that those two expressions have the same value, so we write
Then we simplify those expressions <--> <--> <-->
Then we subtract 2 from both sides <--> <-->
Then we subtract n from both sides <--> <-->
So our first odd integer is 32. The others are 33 and 35.
Let's verify. The sun of the first 2 is
and 29 more than the third one is .
We found the three consecutive odd integers the problem talks about. They are
31, 33, and 35.
