SOLUTION: Can you help me solve {{{k+2k+k sqrt(3)=47}}}

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Question 548338: Can you help me solve k%2B2k%2Bk+sqrt%283%29=47
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
3k +ksqrt(3)=47
k(3+sqrt(3))=47
k=47/(3+sqrt(3))
rationalize the denominator
k=(47(3-sqrt(3))/((3+sqrt(3))(3-sqrt(3))
k=141-47sqrt(3)/(9-3)
k=((141/6)-47sqrt(3))/6)
k=47/2 - 47/sqrt(3)
k=47/2(1-sqrt(3))
m.ananth@hotmail.com