SOLUTION: Factor completely: 6a^2b-12a^3b^2+36ab
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Question 548331
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Factor completely: 6a^2b-12a^3b^2+36ab
Answer by
nerdybill(7384)
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6a^2b-12a^3b^2+36ab
factor out a 6:
6(a^2b-2a^3b^2+6ab)
factor out an 'a':
6a(ab-2a^2b^2+6b)
factor out an 'b':
6ab(a-2a^2b+6)