SOLUTION: Can someone help me solve this problem? At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels sout

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Question 54833: Can someone help me solve this problem?
At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart?
Thanks, Lyn
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart?
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North car DATA:
rate=55 mph ; time= x hrs. ; distance= 55x mi.
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South car DATA:
rate= 60 mph ; time= x-1 hrs ; distance = 60(x-1)=60x-60 miles
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EQUATION:
south distance+ north distace = 285 miles
60x-60+55x=285
115x=345
x=3 hrs
1:00p.m.+3 hrs. = 4:00p.m.
Cheers,
Stan H.