SOLUTION: Write and graph an equation for the parabola that has vertex (-1, 3) and passes through the point (-2, 1). Remember: y= a(x-h)2 + k

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write and graph an equation for the parabola that has vertex (-1, 3) and passes through the point (-2, 1). Remember: y= a(x-h)2 + k      Log On


   

Question 548276: Write and graph an equation for the parabola that has vertex (-1, 3) and passes through the point (-2, 1). Remember: y= a(x-h)2 + k
Answer by lwsshak3(11628) About Me  (Show Source):
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Write and graph an equation for the parabola that has vertex (-1, 3) and passes through the point (-2, 1). Remember: y= a(x-h)2 + k
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y= a(x-h)^2 + k
y= a(x+1)^2 + 3
plug in coordinates of given point (-2,1) to find a
1= a(-2+1)^2 + 3
1= a(-1)^2 + 3
1= a + 3
a=-2
Equation:
y= -2(x+1)^2 + 3
see graph below:
+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+-2%28x%2B1%29%5E2+%2B+3%29+