SOLUTION: (8^2/3*27^3/2)/(16^3/4*9^3/4) the 2/3 etc are fractional exponents (indices) not actual fractions I cannot seem to work this out. I have tried with the algibrator program but it s

Algebra ->  Exponents -> SOLUTION: (8^2/3*27^3/2)/(16^3/4*9^3/4) the 2/3 etc are fractional exponents (indices) not actual fractions I cannot seem to work this out. I have tried with the algibrator program but it s      Log On


   

Question 548109: (8^2/3*27^3/2)/(16^3/4*9^3/4) the 2/3 etc are fractional exponents (indices) not actual fractions
I cannot seem to work this out. I have tried with the algibrator program but it seems to take a million steps for what at first appears to be a not too complicated problem. I have tried to reduce the whole numbers to , for example 8 to 2^4 etc. I do not know if this will appear correctly in the text so I will describe the problem. 8 with the fractional indices 2 over 3 times 27 with the fractional indices 3 over 4 all over 16 with the fractional indices 3 over 4 times 9 with the fractional indices 3 over 4

Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!

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Recall.
+x%5Ea+%2A+y%5Eb+=+x%2Ay%5E%28a%2Bb%29+
+x%5Ea+%2F+y%5Eb+=+%28x%2Fy%29%5E%28a-b%29+
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We also can apply what we know about the distributive property and fraction.
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