Question 547950: Hi, I tried this question out a bunch of times, but I can't find the answer. Here is the question: "Mark has 26 nickels, dimes and quarters, altogether totaling $3.00. He has twice as many dimes as
nickels. Find the number of each coin that he has"
And I was taught not to do q for quarters, d for dimes, or n for nickels. here is an example.
" A student has $5.90 in dimes and quarters. There are 32 coins altogether. How many of each coin
does the student have?"
the let statements I would write would be:
Let x= dimes
Let 32-x= quarters.
Sorry if this is confusing but I would like if you could try to help. You can do the q, d, or n, but if you could do it the way i learned it that would really help.
Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website! I personally like the q,d,n method but I can do it
the other way, too.
There are 26 coins, and it is given:
 , so I now have
 ,
 , so now I have
n, 2n, 26 - 3n instead of n, d, and q
Now I can say
 ( all in cents )
and, there are  dimes, so
and
 quarters
There are 7 nickels, 14 dimes, and 5 quarters
check answer:
OK
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