SOLUTION: Maybe I missed this part of the lecture, but I just can't figure these out. Here are two examples. Thank you very much. (A) Factor 18x^7 – 12x^4 in the form of ax^b(cx^d + e),

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Maybe I missed this part of the lecture, but I just can't figure these out. Here are two examples. Thank you very much. (A) Factor 18x^7 – 12x^4 in the form of ax^b(cx^d + e),       Log On


   



Question 54779: Maybe I missed this part of the lecture, but I just can't figure these out. Here are two examples. Thank you very much.
(A) Factor 18x^7 – 12x^4 in the form of ax^b(cx^d + e), where a, b, c, d, and e are integers and a > 0. Put integers a, b, c, d and e in the 1st, 2nd, 3rd, 4th and 5th answer boxes, respectively.
(B) Factor 15x^8 + 10x^5 – 35x^2 in the form of ax^b(cx^d + ex^f + g), where a, b, c, d, e, f and g are integers and a, b > 0, d > f > 0. Put a, b, c, d, e, f, and g in the 1st, 2nd, 3rd, 4th, 5th, 6th and 7th answer boxes, respectively.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Factor:
A) 18x%5E7+-+12x%5E4 Look for common multiples in each term: Looking at 18 and 12, the GCM is 6 because: 3(6) = 18 and 2(6) = 12 so you can factor 6 from the expression.
Now look at the variables (x's), x%5E7 and x%5E4 The GCM would be x%5E4 because: %28x%5E4%29%28x%5E3%29+=+x%5E7 and %28x%5E4%29%28x%5E0%29+=+x%5E4 (x%5E0+=+1) so you can factor x%5E4 from the expression. Putting it all together, you get:
18x%5E7+-+12x%5E4+=+6x%5E4%283x%5E3-2%29
Do you see the idea here?
B) 15x%5E8+%2B+10x%5E5+-+35x%5E2 For the integers, the GCM would be 5 because: 15 = 5(3), 10 = 5(2), and 35 = 5(7)
For the x's the GCM would be x%5E2 because: x%5E8+=+%28x%5E2%29%28x%5E6%29, x%5E5+=+%28x%5E2%29%28x%5E3%29, and x%5E2+=+%28x%5E2%29%28x%5E0%29 (x%5E0+=+1) Putting it all together, you get:
15x%5E8+%2B+10x%5E5+-+35x%5E2+=+5x%5E2%283x%5E6+%2B+2x%5E3+-+7%29