SOLUTION: Hi, I have to solve for y in terms of x with this problem log6Y = LOG6 4- Log6 X I'm not sure how to even start this problem. Any help is appreciated. Thank you Beth

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi, I have to solve for y in terms of x with this problem log6Y = LOG6 4- Log6 X I'm not sure how to even start this problem. Any help is appreciated. Thank you Beth      Log On


   

Question 547736: Hi, I have to solve for y in terms of x with this problem log6Y = LOG6 4- Log6 X
I'm not sure how to even start this problem. Any help is appreciated. Thank you
Beth
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
log%28base6%29y=log%28base6%294-log%28base6%29x
We need to first make the right hand side into one log using the rule
log(a)+log(b)=log(ab)
So we have:
log%28base6%29y=log%28base6%29%284%2Ax%29
Now to get rid of the logs, we take raise the whole thing to it's base(normally logs are base 10, but in this case it is base 6):
6%5E%28log%28base6%29y%29=6%5E%28log%28base6%29%284%2Ax%29%29
y=4x

Hopefully this helps:) let me know if you are still unsure.