Please help me solve:
(5x) + 6 > 3x
On the left side of the equation, get rid of any term that
DOES NOT contain an x and you KEEP anything that DOES contain x.
On the right side it's the other way around. You have to get
rid of anything that DOES NOT contain x and KEEP anything that
DOES contain x.
The terms on the left are "(3x)", and "+ 6,"
Get rid of the + 6 because that does not contain an x
There is only one term on the right, "3x". It DOES contain an x
so you want to get rid of it.
But we will get rid of the 6 on the left first.
To do that we add its opposite "- 6" to both sides.
Add "- 6" to the left side by putting the "- 6" underneath the
"+ 6" on the left. There are no terms wiuthout x on the right
side so just add it by writing it far to the right. Then draw a
line and add vertically:
(5x) + 6 > 3x
- 6 - 6
-----------------
(5x) > 3x - 6
There is really no need for those parentheses, so we can just
take them off
5x > 3x - 6
Now we have no more terms on the left that DO NOT contain x. So we
look at the right side. It contains as its only term 3x, and that
has an x in it. So wew get rid of it by adding its opposite to both
sides.
5x > 3x - 6
-3x -3x
------------
2x > - 6
Now we only need to get rid of the 2 coefficient of x,
so that we'll just have x left. We get rid of a coefficient
by dividing both sides by it. So w divide both sides by 2:
2x - 6
---- > ------
2 2
Now the 2'a cancel on the left, and on the right the 2
cancels into the 6 and we get - 3.
1 - 3
2x - 6
---- > ------
2
1 1
So you just have
x > -3
It's just like an equation. But if we had divided by
a negative we would have had to reverse the inequality. But we
divided by a positive (positive 2, that is), so we did not rever
the inequality symbol. But in another problem you will have to
reverse the inequality, just not in this one. You reverse the
inequality ONLY when you didvide by a NEGATIVE NUMBER
Edwin
