SOLUTION: graph the function - label vertex and axis of symmetry y=-(x+3)^2 + 5

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Question 547728: graph the function - label vertex and axis of symmetry
y=-(x+3)^2 + 5

Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
So for any parabola, we have the following possible transformations:
y=a%28x-h%29%5E2%2Bk
where (h,k) is the vertex, and a is the dilation and reflection.

So from this we can see that (-3,5) is the vertex, and we are reflecting it along the x axis (since a=-1).

So we have y=x^2(the base function) to begin
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2Cx%5E2%29
And now we reflect it along the x axis
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-x%5E2%29

And we use the vertex point (or slide the whole thing to the left 3 units and up 5 units
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-%28x%2B3%29%5E2%2B5%29


We can also make a table of values and check if they match with our graph.
Hopefully this helps!