SOLUTION: Find four consecutive multiples of 7 such that 4 times the sum of the first multiple and 2 is 15 greater than 3 times the third.

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Question 547481: Find four consecutive multiples of 7 such that 4 times the sum of the first multiple and 2 is 15 greater than 3 times the third.
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Define the numbers as:
x
x+7
x+14
x+21
.
4(x+2) = 3*(x+14)+15
.
4x +8 = 3x +42 + 15
x = 49
x+7 = 56
x+14 = 63
x+21 = 70
.
Answer: The numbers are 49, 56, 63, and 70.
.
Done.