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Question 547385: Two hoses are filling a swimming pool. The hose with the larger diameter supplies 1.5 times as much water as the hose with the smaler diameter. The larger hose is on for 2hrs before the smaller hose is turned on. If 5 hours after the larger hose is turned on there are 3150 gallons of water in the pool, find the rate of flow from each hose?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Two hoses are filling a swimming pool.
The hose with the larger diameter supplies 1.5 times as much water as the hose with the smaller diameter.
The larger hose is on for 2hrs before the smaller hose is turned on.
If 5 hours after the larger hose is turned on there are 3150 gallons of water in the pool, find the rate of flow from each hose?
:
let r = the flow rate of the smaller hose
then
1.5r = the flow rate of the larger
:
From the information given: large hose was on for 5 hrs, the smaller for 3 hrs:
:
5(1.5r) + 3r = 3150 gal
7.5 + 3r = 3150
10.5r = 3150
r = 3150/10.5
r = 300 gal/hr, flow rate of the smaller hose
and
1.5(300) = 450 gal/hr, flow rate of the larger
:
:
Check this: 5(450) + 3(300) = 3150
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