SOLUTION: Please help I am struggling with the last portion of this where I need to use the equation the number of regular admissions sold was 10 more than twice the number of child tickets

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Question 547367: Please help I am struggling with the last portion of this where I need to use the equation the number of regular admissions sold was 10 more than twice the number of child tickets sold. This is the question. 210 people attended a school carnival. The total dollars earned at the carnival was $710. Tickets for regular admission were $5, student tickets were $3, and children under 5 were $1. The number of regular admissions sold was 10 more than twice the number of child tickets sold. How many of each type of ticket were sold? So far I got two equations: +x%2By%2Bz=210+ and +5x%2B3y%2B1z=710 . But I can't for the life of me figure out the final equation. Please help as soon as possible.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
210 people attended a school carnival. The total dollars earned at the carnival was $710. Tickets for regular admission were $5, student tickets were $3, and children under 5 were $1. The number of regular admissions sold was 10 more than twice the number of child tickets sold. How many of each type of ticket were sold? So far I got two equations
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r + s + c = 210
5r + 3s + c = 710
r = 2c + 10
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Makes it easy to sub for r
Can you finish it?