SOLUTION: 24x^2y-12x^2+20xy-10x is the polynomial I am supposed to factor out. I factor with 2x the first time around, I am then left with 2x[3x(4y-2)5(2y-1)] in which I do not have "twi

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 24x^2y-12x^2+20xy-10x is the polynomial I am supposed to factor out. I factor with 2x the first time around, I am then left with 2x[3x(4y-2)5(2y-1)] in which I do not have "twi      Log On


   



Question 547345: 24x^2y-12x^2+20xy-10x is the polynomial I am supposed to factor out.
I factor with 2x the first time around, I am then left with 2x[3x(4y-2)5(2y-1)] in which I do not have "twin parenthesis, what am I doing wrong here?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
24x^2y-12x^2+20xy-10x
-----------------
2x(12xy -6x +10y - 5)
------
2x[6x(2y-1)+5(2y-1)]
-----
2x(2y-1)(6x+5)
=======
Cheers,
Stan H.
=================