SOLUTION: A cunning farmer, when asked how many sheep he had,said,"A third of my sheep are in the barn. A fifth are out to pasture. Three times the difference of these are newborn. And one i

Algebra ->  Human-and-algebraic-language -> SOLUTION: A cunning farmer, when asked how many sheep he had,said,"A third of my sheep are in the barn. A fifth are out to pasture. Three times the difference of these are newborn. And one i      Log On


   



Question 54733This question is from textbook
: A cunning farmer, when asked how many sheep he had,said,"A third of my sheep are in the barn. A fifth are out to pasture. Three times the difference of these are newborn. And one is my daughter's pet. But there's less than 20 in all." How many sheep does the farmer have? This question is from textbook

Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Let the no. of sheeps be x.
Then, no. of sheeps in barn = x%2F3.
No. of sheeps out in pasture = x%2F5.
No. of new-born sheeps = 3%28x%2F3+-+x%2F5%29 = 2x%2F5.
1 sheep is his daughter's pet.
Thus, total no. of sheeps = x%2F3+%2B+x%2F5+%2B+2x%2F5+%2B+1 = 14x%2F15+%2B+1
But we already assumed that the total no. of sheeps is x.
So, 14x%2F15+%2B+1+=+x
or x+-+14x%2F15+=+1
or x%2F15+=+1
or +x+=+15
So the farmer had 15 sheeps altogether.
Check: 15 < 20. So given condition is satisfied.