SOLUTION: {{{2p^(2)-119=3p}}}

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Question 547274: 2p%5E%282%29-119=3p
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
2p%5E%282%29-119=3p
Since we have a p%5E2 term (and this is the biggest term), a p term and a constant, it is a quadratic. We can put it into ax%5E2%2Bbx%2Bc=0 form.
2p%5E%282%29-3p-119=0
We could try to think of two numbers that multiply to 2%2A-119 and add to -3. But this may be hard to think of. Instead we will use the quadratic formula which states (I will use p instead of x, though x is most commonly used):
p=%28-%28b%29%2B+sqrt%28%28b%29%5E2-4%28a%29%28c%29%29%29%2F2%28a%29
or
p=%28-%28b%29-+sqrt%28%28b%29%5E2-4%28a%29%28c%29%29%29%2F2%28a%29


p=%28-%28-3%29%2B+sqrt%28%28-3%29%5E2-4%282%29%28-119%29%29%29%2F2%282%29
p=%283%2B+sqrt%289%2B952%29%29%2F4
p=%283%2B+sqrt%28961%29%29%2F4
p=%283%2B+31%29%2F4
p=%283%2B31%29%2F4
p=34%2F4
p=8.5
OR
p=%28-%28-3%29-+sqrt%28%28-3%29%5E2-4%282%29%28-119%29%29%29%2F2%282%29
p=%283-+sqrt%289%2B952%29%29%2F4
p=%283-+sqrt%28961%29%29%2F4
p=%283-+31%29%2F4
p=%283-31%29%2F4
p=-28%2F4
p=-7