SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 90 miles per hour. Train A passes a sta

Algebra ->  Equations -> SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 90 miles per hour. Train A passes a sta      Log On


   



Question 547248: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 90 miles per hour. Train A passes a station at 10:10 P.M. If train B passes the same station at 10:40 P.M. at what time will train B catch up to train A?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
At 10:40 PM, train B will be 0 miles past the station. x hours after that, it will be 90x miles past the station.
At 10:40 PM, train A will be 40 miles past the station, after traveling away from that station for 30 minutes (0.5 hours), covering 40 miles since 10:10 PM. x hours after 10:40 PM, train A will be 40%2B80x miles away from that station.
At some point they will be the same distance from that station, and train B will be overtaking train A. At that point, we will have:
90x=40%2B80x --> 10x=40 --> x=4
So, 4 hours after 10:40 PM, both trains will be at the same distance from the station and a few passengers in train B will be waving at a few passengers in train A, as B passes A. The rest of the passengers will probably be asleep, because it will be 2:40 AM.