SOLUTION: Sorry I submitted this question wrong the last time. One little mistake makes all the difference. 3/x^2+4x+3 - 1/x^2-9 Sorry for the mistake! I appreciate your help! ac

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Sorry I submitted this question wrong the last time. One little mistake makes all the difference. 3/x^2+4x+3 - 1/x^2-9 Sorry for the mistake! I appreciate your help! ac      Log On


   



Question 54721: Sorry I submitted this question wrong the last time. One little mistake makes all the difference.
3/x^2+4x+3 - 1/x^2-9
Sorry for the mistake! I appreciate your help!
ac

Answer by wgomero(28) About Me  (Show Source):
You can put this solution on YOUR website!
resolution:
3/x^2 + 4x + 3 - 1/x^2 -9 =0;
3/x^2 -1/x^2 + 4x - 6 =0;
2/x^2 + 4x - 6 =0
2 + 4x^3 - 6x^2 =0
4x^3 - 6x^2 + 2 = 0
2(2x^3 - 3x^2 + 1)=0