SOLUTION: This year, 75% of the graduating class of Harriet Tubman High School had taken at least 8 math courses. Of the remaining class members, 60% had taken 6 or 7 math courses. What perc

Algebra ->  Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: This year, 75% of the graduating class of Harriet Tubman High School had taken at least 8 math courses. Of the remaining class members, 60% had taken 6 or 7 math courses. What perc      Log On


   



Question 547146: This year, 75% of the graduating class of Harriet Tubman High School had taken at least 8 math courses. Of the remaining class members, 60% had taken 6 or 7 math courses. What percent of the graduating class had taken fewer than 6 math courses?
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
if 75% had 8 classes the the other 25% had less than 8
so if 60% of that 25% had 6+ the that leaves 40% of that 25 with fewer than 6
to make this easier im going to say theres 100 students in the class
25% is 25 students and 40% of 25 is .4(25)=10 so 10 divided by total 100 students multiplied by 100%: 10%2F100*100%=10%
there might not be 100 students but it makes getting the % easier to see Ill show below that any number of students could be used and still get 10% as answer
.
if there were 3948273645 in the class 25% is .25%283948273645%29=98706411.25 and 40% of that is .4%2898706411.25%29=394827364.5
so then 394827364.5%2F3948273645=.1 .1%2A100=10%