SOLUTION: (a) State the domain of {{{f(x) = ln(x + 2)}}}. (b) Solve for x: {{{ln(x+2)=3}}}

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: (a) State the domain of {{{f(x) = ln(x + 2)}}}. (b) Solve for x: {{{ln(x+2)=3}}}      Log On


   

Question 547065: (a) State the domain of f%28x%29+=+ln%28x+%2B+2%29.
(b) Solve for x: ln%28x%2B2%29=3
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
a) We know that we cannot take ln of a negative number (or 0) which means:
x%2B2%3E0
x%3E-2
b) ln%28x%2B2%29=3
We need to get rid of the ln. The opposite of ln is e. This leaves:
e%5E%28ln%28x%2B2%29%29=e%5E3
x%2B2=e%5E3
x=e%5E3-2