SOLUTION: Using the approximate values: log(underscore 5) (6)= 1.1 and log(underscore 5) (10) = 1.4, find: Log(underscore 5) (1000). Also, log(underscore 5) (5) = 1. Example: Using those

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Using the approximate values: log(underscore 5) (6)= 1.1 and log(underscore 5) (10) = 1.4, find: Log(underscore 5) (1000). Also, log(underscore 5) (5) = 1. Example: Using those       Log On


   



Question 546661: Using the approximate values: log(underscore 5) (6)= 1.1 and log(underscore 5) (10) = 1.4, find: Log(underscore 5) (1000). Also, log(underscore 5) (5) = 1.
Example: Using those values, find log(underscore 5) (30). The answer would be log(underscore 5) (5 * 6) which is log(underscore 5) (5) plus log(underscore 5) 6 which is 1 + 1.1 which equals 2.1
I dont know how to get 1000 out of those values.

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
10*10*10 = 1000