You can put this solution on YOUR website! log(x-9)=1-logx
log(x-9)+logx=1
adddition in logs indicates multiplication in operations
log[(x-9)*x]=1
convert to exponential form: base(10) raised to log of number(1)=number[(x-9)*x]
10^1=[(x-9)*x]
x^2-9x-10=0
(x-10)(x+1)=0
x=-1 (reject, x>0)
or
x=10 (ans)