SOLUTION: log2(x + 2) + log2(x - 4) = 4

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Question 546006: log2(x + 2) + log2(x - 4) = 4
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve for x
log2(x + 2) + log2(x - 4) = 4
log2[(x+2)(x-4)]=4
change to exponential form: Base(2) raised to log of number(4)=number[(x+2)(x-4)]
..
2^4=(x+2)(x-4)
16=x^2-2x-8
x^2-2x-24=0
(x-6)(x+4)=0
x=6
or
x=-4 (reject, (x+2)>0)