SOLUTION: How do I find "all real zeros" of the function? f(x) = x^3-3x^2-x+3

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How do I find "all real zeros" of the function? f(x) = x^3-3x^2-x+3      Log On


   

Question 54595: How do I find "all real zeros" of the function?
f(x) = x^3-3x^2-x+3
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29+=+x%5E3-3x%5E2-x%2B3
f%28x%29+=+x%5E2%28x-3%29-%28x-3%29
f%28x%29+=+%28x%5E2-1%29%28x-3%29
f%28x%29+=+%28x%2B1%29%28x-1%29%28x-3%29
Thus f(x) becomes zero when x = -1,1,3. Hence f(-1), f(1), f(3) are the zeros.