SOLUTION: 62. 1/3 [ 2x - 1 ] greater than 1 the brackets after the 1/3 and after -1 stand for the absolute value sign i do not knwo how to put that in 72. 3x – 7 ] greater than or equa

Algebra ->  Absolute-value -> SOLUTION: 62. 1/3 [ 2x - 1 ] greater than 1 the brackets after the 1/3 and after -1 stand for the absolute value sign i do not knwo how to put that in 72. 3x – 7 ] greater than or equa      Log On


   



Question 54592: 62. 1/3 [ 2x - 1 ] greater than 1
the brackets after the 1/3 and after -1 stand for the absolute value sign i do not knwo how to put that in
72. 3x – 7 ] greater than or equal to -3
like i said i do not knwo how to put in for an absolute value for the greater than signs
Can you please help and maybe offer me assistance in how to put the sign in the equation
thank you in advance

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
These are the steps you will use for both of your problems.
Isolate the absolute value on one side of the inequality sign.
If the inequality sign is now |x|>k, solve two problems for x: x>k or x<-k.
:
62)
%281%2F3%29%2Aabs%282x-1%29%3E1
3%281%2F3%29%2Aabs%282x-1%29%3E3%281%29
abs%282x-1%29%3E3
2x-1%3E3 or 2x-1%3C-3
2x-1%2B1%3E3%2B1 or 2x-1%2B1%3C-3%2B1
2x%3E4 or 2x%3C-2
2x%2F2%3E4%2F2 or 2x%2F2%3C-2%2F2
x%3E2 or x%3C-1
:
72)
This one is solvable without solving it |x|>-k is all real numbers, the opposite |x|<-k is no solution. Because absolute values result in positive numbers. Let's solve it for fun anyways:
abs%283x-7%29%3E-3
3x-7%3E-3 or 3x-7%3C3
3x-7%2B7%3E-3%2B7 or 3x-7%2B7%3C3%2B7
3x%3E4 or 3x%3C10
3x%2F3%3E4%2F3 or 3x%2F3%3C10%2F3
x%3E4%2F3 or x%3C10%2F3
That is all real numbers, let me show you why on a number line:
x>1 1/3 or x< 3 1/3
<<=======[============]=======>>
-1,0,1,1 1/3, 2, 3, 3 1/3, 4
I know it's hard to see, but the whole number line is shaded.
Happy Calculating!!!