You can put this solution on YOUR website! YOU CAN ONLY FIND THE AREA OF A TRIANGLE GIVEN ONE SIDE OF THE TRIANGLE IS 5 -- IF THE TRIANGLE IS AN EQUILATERAL TRIANGLE (ALL SIDES ARE EQUAL)
THEN THE AREA IS A=(1/2)B*H. THE H IS FOUND BY SOLVING THE EQUATION A^2+B^2=C^2 AND WE HAVE ONE SIDE=5/2 OR 2.5 (SIDE A OR B) AND C=5 THUS
5^2=2.5^+B^2 OR 25=6.25+B^2 OR 25-6.25-B^2 OR B^2=18.75 OR B=SQRT18.75
OR 4.33 = THE HEIGHT OF THE TRIANGLE THUS THE AREA A=(1/2)5*4.33 OR
A=21.65/2 OR A=10.825
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