Question 545805: cos(arcsin(-3/5))
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! cos(arcsin(-3/5))
arcsin(-3/5) is a reference angle whose sin=-3/5 in quadrant IV where sin<0 and cos>0.
note: arcsin(-3/5) could also be in quadrant III where sin is also<0, but its domain is: [-π/2, π/2]
..
cos of this same reference angle=4/5
Therefore, cos(arcsin(-3/5))=4/5
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