SOLUTION: log(6x+5)=1+log(x-8)

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Question 545749: log(6x+5)=1+log(x-8)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
log(6x+5)=1+log(x-8)
log(6x+5)-log(x-8)=1
log[(6x+5)/(x-8)]=1
exponential form: base(10) raised to log of number(1)=number[(6x+5)/(x-8)]
10^1=(6x+5)/(x-8)=10
6x+5=10x-80
4x=85
x=21.25