SOLUTION: A ball is thrown straight upin the air from a height of 6 feet at a speed of 80 feet per second. The height of the ball in feet is given by -16t^2 + 80t + 6 where t is the time in
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-> SOLUTION: A ball is thrown straight upin the air from a height of 6 feet at a speed of 80 feet per second. The height of the ball in feet is given by -16t^2 + 80t + 6 where t is the time in
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Question 545578: A ball is thrown straight upin the air from a height of 6 feet at a speed of 80 feet per second. The height of the ball in feet is given by -16t^2 + 80t + 6 where t is the time in seconds. What is the height of the ball after 3 seconds Answer by jerryguo41(197) (Show Source):
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1) Basic physics formula for anything that has initial velocity is t= number of seconds; x= inital velocity (i.e. how hard was it thrown); h= initial height
2)Plug three in where you see a "t"
3) Square then multiply
4) Simplify
5) At three seconds the ball is 102ft off the ground
