SOLUTION: solve by removing factors of one (42y^6/49y^3) uh how in the world do you do this?

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Question 545465: solve by removing factors of one (42y^6/49y^3) uh how in the world do you do this?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
factors of one are fractions where the numerator equals the denominator, so the fraction is equal to one

%2842y%5E6%29%2F%2849y%5E3%29 = %287%2A6%2Ay%5E3%2Ay%5E3%29%2F%287%2A7%2Ay%5E3%29 = %287%2F7%29%28y%5E3%2Fy%5E3%29%28%286%2Ay%5E3%29%2F7%29

factoring out the "ones" leaves you with a reduced fraction