SOLUTION: 3b2-4b+3 (6b4+4b3-4b2+6b+7)
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Question 545365
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3b2-4b+3 (6b4+4b3-4b2+6b+7)
Answer by
jim_thompson5910(35256)
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3b^2-4b+3(6b^4+4b^3-4b^2+6b+7)
3b^2-4b+18b^4+12b^3-12b^2+18b+21
18b^4+12b^3-9b^2+14b+21
So 3b^2-4b+3(6b^4+4b^3-4b^2+6b+7) = 18b^4+12b^3-9b^2+14b+21