SOLUTION: Hope I am in the right place with this question. Factor each of the following trinomials completely. 2a^3-52a^2b+96ab^2. I got as far as ... 2a(a^2-26ab+48b^2). Then I

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Hope I am in the right place with this question. Factor each of the following trinomials completely. 2a^3-52a^2b+96ab^2. I got as far as ... 2a(a^2-26ab+48b^2). Then I       Log On


   

Question 54535This question is from textbook Beginning Algebra
: Hope I am in the right place with this question.
Factor each of the following trinomials completely.
2a^3-52a^2b+96ab^2.
I got as far as ...
2a(a^2-26ab+48b^2). Then I got completely lost. This question is from textbook Beginning Algebra

Found 3 solutions by Nate, Earlsdon, funmath:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
2a(a^2 - 26ab + 48b^2) factors of 48 that sum to -26 ~> -2 and -24
2a(a - 2b)(a - 24b)

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Ok, your first step is fine.
2a%28a%5E2-26ab%2B48b%5E2%29 Now you can factor the parentheses:
2a%28a-2b%29%28a-24b%29 ...and you're done!

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
You got the first step right.
2a%5E3-52a%5E2b%2B96ab%5E2
2a%28a%5E2-26ab%2B48b%5E2%29
a%2Aa=a%5E2 and b%2Ab=b%5E2 so...
2a%28a___b%29%28a___b%29
Two numbers that multiply together to give you +48, but add together to give you -26 are -2 and -24.
2a%28a-24b%29%28a-2b%29
Happy Calculating!!!