SOLUTION: how do we solve log8=logx+log(2x)

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Question 545107: how do we solve log8=logx+log(2x)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
Log%288%29+=+Log%28x%29%2BLog%282x%29 Apply the "Product rule" to the right side:
Log%5Bb%5D%28M%29%2BLog%5Bb%5D%28N%29+=+Log%5Bb%5D%28M%2AN%29.
Log%288%29+=+Log%28x%2A2x%29
Log%288%29+=+Log%282x%5E2%29 If Log%5Bb%5D%28M%29+=+Log%5Bb%5D%28N%29 then M+=+N
8+=+2x%5E2 Divide by 2.
4+=+x%5E2 Take the square root.
2+=+x or x+=+2