SOLUTION: how do we solve log16-log2x=4?

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Question 545106: how do we solve log16-log2x=4?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
solve log(16) - log(2x) = 4
subtraction means divide, so write
log%28%2816%2F%282x%29%29%29 = 4
Simplify,cancel 2
log%28%288%2Fx%29%29 = 4
write the exponent equiv of logs
10%5E4 = 8%2Fx
10000x = 8
x = 8%2F10000
x = .0008
:
:
Check this on your calc: enter log(16) - log(2*.0008), results: 4