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Question 54494: determine wheather the given function is even, odd, or neither....thanks
f(x)=5x^2+x^4
Answer by Born2TeachMath(20)   (Show Source):
You can put this solution on YOUR website! An even function is one where all of the exponents of x are even numbers.
An odd function is one where all of the exponents of x are odd numbers.
A function is neither if the exponents of x are both even and odd.
And remember that constants (numbers by themselves) are of even power, since 3 = 3*(x^0)!!
Therefore, your function:
f(x) = 5x^2 + x^4 is an even function, since 2 and 4 are both even (x^2 and x^4).
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