SOLUTION: The problem I have is 4x – 3 = x – y. I need to graph this but I don't understand how to get there, teacher didn't cover an equation like this. I have tried subtracting x from both

Algebra ->  Graphs -> SOLUTION: The problem I have is 4x – 3 = x – y. I need to graph this but I don't understand how to get there, teacher didn't cover an equation like this. I have tried subtracting x from both      Log On


   



Question 544847: The problem I have is 4x – 3 = x – y. I need to graph this but I don't understand how to get there, teacher didn't cover an equation like this. I have tried subtracting x from both sides leaving 3x - 3 = -y but I don't see how you would get graph points from that. Could you please explain how I can solve this problem? I don't want just the answer, i'd like to know how to solve for future reference.
Again, graph 4x-3=x-y

Found 3 solutions by saifoo.khan, rapaljer, josmiceli:
Answer by saifoo.khan(162) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
4x – 3 = x – y.
The best way for graphing is,
convert the line into y=mx + b form.
then use this;
ALWAYS REMEMBER,
When y intercepts, put x= 0
When x intercepts, put y= 0
Now solving your equation,
4x – 3 = x – y.
-y + x = -3 + 4x
-y = 4x - x - 3
-y = 3x - 3
y = -3x + 3
now this tells us that the slope is -3 and the y intercept is 3.
Well, moving on.
Finding x intercept,
put y = 0
y = -3x + 3
0 = -3x + 3
-3 = -3x
3 = 3x
3/3= x
x = 1
So u got x intercept = x=1
now the line with cut the x axis at 1.
and y axis at 3.

BINGo!! =D

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Your first step is correct. Now, to solve for y, multiply both sides by -1, and you get

-1(3x-3)=-1*-y
-3x+3 = y
y=-3x+3

Now, the slope is -3 and the y intercept is 3, and it looks like this:

+graph%28300%2C300%2C-6%2C6%2C-6%2C6%2C+-3x%2B3%29+

For more help on the topic of graphing and a NON-traditional explanation of Graphing, please see my own website. Click on my tutor name anywhere in algebra.com. This takes you to the homepage of my website. Near the top of my homepage, look for "Basic, Intermediate, and College Algebra: One Step at a Time." Choose either Basic Algebra or Intermediate Algebra. In Basic Algebra, look in Chapter 4; in Intermediate Algebra, look in Chapter 5 for the topic Graphing.

There is also a video from my younger days in which I taught the topic of Graphing and Slope of a Line. You can find this video at the link on my homepage called "Rapalje Videos in Living Color," then "Basic Algebra". This video is FREE, as well as everything on my website.

Since most of my career was spent teaching math IN COLOR, this became a major theme in my teaching career. In case you forget my name or can't remember how to spell it, an easy way to find my website is to go to the link www.mathinlivingcolor.com.

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You need to get the equation into the form
+y+=+m%2Ax+%2B+b+
m is the slope of the line
b is the y-intercept
( y-value where line crosses y-axis )
-----------------------------
+4x+-+3+=+x+-+y+
You can think of +-y+ as +%28-1%29%2Ay+,
but you want just y, so add y
to both sides
+4x+-+3+%2B+y+=+x+
Now subtract +4x+ from both sides
+-3+%2B+y+=+x+-+4x+
Now add 3 to both sides
+y+=+-3x+%2B+3+
---------------
Now it is in the correct form. the slope is +-3+
The y-intercept is 3, so that gives you the point
(0,3)
-------
To find the x-intercept, set y=0
+0+=+-3x+%2B+3+
Subtract 3 from both sides
+-3+=+-3x+
Divide both sides by -3
+1+=+x+
Now you have the point (1,0)
------------------------
2 points determine a line, so that's
all you need
Here's a plot:
+graph%28+400%2C+400%2C+-6%2C+6%2C+-6%2C+6%2C+-3x+%2B+3%29+