SOLUTION: a ball is thrown straight up from a rooftop 240ft high. The ball misses the rooftop on the way down.When will the ball be at 120 ft. identify solution on a graph h=-16t^2+56t+240
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: a ball is thrown straight up from a rooftop 240ft high. The ball misses the rooftop on the way down.When will the ball be at 120 ft. identify solution on a graph h=-16t^2+56t+240
Log On
Question 544765: a ball is thrown straight up from a rooftop 240ft high. The ball misses the rooftop on the way down.When will the ball be at 120 ft. identify solution on a graph h=-16t^2+56t+240 Found 2 solutions by stanbon, Alan3354:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! h=-16t^2+56t+240
----
Solve: -16t^2+56t+240 = 0
-----
-8(2t^2 - 7t + 30) = 0
-----
Quadratic Formula:
-----
t = [7 +- sqrt(49 - 4*2*30)]/4
----
t = [7 +- sqrt(-191)]/4
---
t = [7 + isqrt(191)]/4 or t = [7 - isqrt(191)]/4
=============
Cheers,
Stan H.
=============
You can put this solution on YOUR website! a ball is thrown straight up from a rooftop 240ft high. The ball misses the rooftop on the way down.When will the ball be at 120 ft. identify solution on a graph h=-16t^2+56t+240
-------------
The 56 is the speed of the upward throw, 56 ft/sec
----------------
h=-16t^2+56t+240
----
Solve: -16t^2+56t+240 = 120
-----
-2t^2 + 7t + 15 = 0
---------------------