SOLUTION: 24y^2+2y-2=0
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Question 544740
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24y^2+2y-2=0
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24y^2+2y-2 = 0
Divide every term by 2.
2(12y^2 + y - 1) = 0
12y^2 + y - 1 = 0
12y^2 + 4y - 3y - 1 = 0
12y^2 + 4y becomes 4y(3y + 1)
-3y - 1 becomes -(3y + 1)
(4y - 1)(3y + 1) = 0
Set each factor to zero and solve for y.
4y - 1 = 0
4y = 1
y = 1/4
3y + 1 = 0
3y = -1
y = -1/3
The answer for y should be y = 1/4 and y = -1/3.