SOLUTION: if the length of a rectangle is 5 ft more than twice its width and the area is 42 ft^2?

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Question 544604: if the length of a rectangle is 5 ft more than twice its width and the area is 42 ft^2?
Answer by friesr(113) About Me  (Show Source):
You can put this solution on YOUR website!
Width = x
lenght = 2x+5
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solve for x
x * (2x+5) = 42
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2x^2 + 5x = 42
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2x^2 + 5x -42 = 0
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(x+6)(2x-7)
x=-6 or x = 7/2
since a lenght cannot be a negative value
x = 7/2
now sub back in to 2x+5 for your lenght.
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