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| Question 544519:  How many 7-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, and 8 if the first digit cannot be 0? Repeated digits are allowed.
 Answer by hitarth(1)
      (Show Source): 
You can put this solution on YOUR website! it will be 7! for 8 digit, (with repetition) the digits given to us to form number will be:-
 1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,4,4,4,4,4.......,8,8,8,8,8,8,8,8
 the numbers formed will be permutation of 64 object to arrange in eight places.
 example 64!/{64-8}! = (64*63*62*61*60*59*58*57)
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