Question 544487: Dear math tutor,
Can you help me find the linear function through the point f(-4)=6 perpendicular to this line y-5=2/3(x+2)
Thank you!
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Can you help me find the linear function through the point f(-4)=6 perpendicular to this line y-5=2/3(x+2)
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standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept
..
y-5=2/3(x+2)
y=(2/3)x+4/3+5
y=(2/3)x+4/3+15/3
y=(2/3)x+19/3
slope=2/3
..
For perpendicular line, slope=-3/2 (negative reciprocal)
equation:
y=(-3/2)x+b
solving for b, using coordinates of given point (-4,6) (From f(-4)=6)
6=-3/2*-4+b
6=6+b
b=0
Equation of perpendicular line: y=-3x/2
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