SOLUTION: Find two consecutive numbers such that the sum of their squares is 35 more than twice the square of the smaller.
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Question 54440: Find two consecutive numbers such that the sum of their squares is 35 more than twice the square of the smaller. Answer by Earlsdon(6294) (Show Source):
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Let x be the smaller number, then x+1 will be the next consecutive number. Simplify and solve for x. Subtract 2x^2 from both sides. Subtract 1 from both sides. Finally, divide both sides by 2. and
Check: = 613 = 613
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