SOLUTION: Solve for x. logx+log(x+3)=1

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Question 544145: Solve for x.
logx+log(x+3)=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x.
logx+log(x+3)=1
**
log[x*(x+3)]=1
log(x^2+3x)=1
convert to exponential form:
10^1=x^2+3x
x^2+3x-10=0
(x+5)(x-2)=0
x=-5 (reject, x>0)
or
x=2