You can put this solution on YOUR website! if sec x = 13/12
what is sec x/2?
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work with more familiar cos function:
sec x = 13/12
cos x = 12/13 (reciprocal of sec x)
..
sec x/2=1/cos x/2
..
cos x/2=√[(1+cos x)/2]=√[(1+12/13)/2]=√[(25/13)/2]=√(25/26)=√25/√26
..
ans:
sec x/2=1/cos x/2=√26/√25