SOLUTION: what is the equation of the conjugate of the hyperbola {{{ 25x^2-16y^2=400 }}}

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Question 544037: what is the equation of the conjugate of the hyperbola +25x%5E2-16y%5E2=400+
Answer by lwsshak3(11628) About Me  (Show Source):
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what is the equation of the conjugate of the hyperbola
25x^2-16y^2=400
Standard form of equation for hyperbola with horizontal transverse axis: (x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k)=(x,y) coordinates of the vertex, a=transverse axis, b=conjugate axis.
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For given equation:
25x^2-16y^2=400
divide by 400
x^2/16-y^25=1
b^2=25
b=5=conjugate axis
note: conjugate axis is a line segment, not an equation.