SOLUTION: I have two questions I'm stumped on. One is Suppose the rectangular TV screen measures 50" on the diagonal and 30" in height. What is its width?
The other is The speed of ligh
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-> SOLUTION: I have two questions I'm stumped on. One is Suppose the rectangular TV screen measures 50" on the diagonal and 30" in height. What is its width?
The other is The speed of ligh
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Question 54383: I have two questions I'm stumped on. One is Suppose the rectangular TV screen measures 50" on the diagonal and 30" in height. What is its width?
The other is The speed of light is approx 3 x 10^5 km/sec. Write an equation which is a function of distance y and time x. Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! Hypotenuse ~> 50 inches
Leg ~> a
Leg ~> 30 inches
a^2 + 30^2 = 50^2
a^2 + 900 = 2500
a^2 = 1600
a = 40
The width is 40 inches exactly.
Distance (y) = Rate (3 x 10^5) * Time (x)
y = 300,000x
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