SOLUTION: solve the inequaility │3x + 2│ + 1 > 5 ?
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Question 543605
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solve the inequaility │3x + 2│ + 1 > 5 ?
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│3x + 2│ + 1 > 5
3X +2 +1 > 5
3X + 3 > 5
3X > 5 - 3
3X > 2
DIVIDE BOTH SIDES BY 3
3X /3 > 2 /3
X > 2 / 3 ....................answer