SOLUTION: Can you please help me solve this equation?
{{{ log(n+9)= log(4n)}}}
It is the log of ten since it is not stated.
Do you switch it to exponential form?
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Exponential-and-logarithmic-functions
-> SOLUTION: Can you please help me solve this equation?
{{{ log(n+9)= log(4n)}}}
It is the log of ten since it is not stated.
Do you switch it to exponential form?
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Question 543473: Can you please help me solve this equation?
It is the log of ten since it is not stated.
Do you switch it to exponential form? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! log(n+9)= log(4n)
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Certainly if log(A) = log(B), A must equal B.
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Your Problem:
n+9 = 4n
3n = 9
n = 3
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Another way to get to the same answer:
log(n+9)= log(4n)
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Write each side as an exponent of 10:
10^(log(n+9)) = 10^(log(4n))
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Then n+9 = 4n
and 3n = 9
so n = 3
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Cheers,
Stan H.
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