SOLUTION: How to solve, i had this for my exam {{{d=sqrt(-144 + 16a^2)}}} Thank you

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Question 543262: How to solve, i had this for my exam
d=sqrt%28-144+%2B+16a%5E2%29
Thank you

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
d+=+sqrt%28-144+%2B+16a%5E2%29
a > 3, to prevent having the square root of a negative number.
:
Assume they want you to solve for a
square both sides and write it like this
-144 + 16a^2 = d^2
16a^2 = d^2 + 144
:
Divide both sides by 16
a^2 = %28%28d%5E2%2B144%29%29%2F16
:
Square both sides and you have
a = sqrt%28%28%28d%5E2%2B144%29%29%2F16%29
:
Extract the square root of 1/16
a = 1%2F4*sqrt%28d%5E2%2B144%29